Pumpjack: Difference between revisions
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== See also == | == See also == | ||
* [[ | * [[Fluid system]] | ||
{{ProductionNav}} | {{ProductionNav}} | ||
{{C|Resource extraction}} | {{C|Resource extraction}} |
Revision as of 16:30, 9 September 2017
Pumpjack |
Recipe |
|
+ + + + → | |
Total raw |
|
+ + + |
Recipe |
|
+ + + + → | |
Total raw |
|
+ + + |
Map color |
|
Fluid storage volume |
1000 |
Health |
200 |
Stack size |
20 |
Dimensions |
3×3 |
Energy consumption |
90 kW (electric) |
Mining time |
0.5 |
Mining speed |
1 |
Mining area |
1 tiles |
Pollution |
10/m |
Module slots |
2 slots |
Prototype type |
|
Internal name |
pumpjack |
Required technologies |
|
Boosting technologies |
|
Produced by |
|
Pumpjacks extract crude oil from oil fields. Each oil field can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 10 multiplied by the field's yield (e.g. 54 crude oil for 538% yield) per second. Without speed modules one pumpjack cycle takes one second to complete.
Extracting oil lowers the field's yield by 1% per 75 pumpjack cycles to a minimum of 20% of the initial yield or 2 oil unit per second, whichever is larger.
Pumpjacks are limited to a maximum output of 100 crude oil per cycle, achieved by an oil field with more than 999% yield. However, such a high yield is fairly rare.
Pumpjacks output tile location is fixed relative to its orientation.
Pumpjacks cannot be placed on a non-oilfield tile.
Tips
If oil fields are depleted ( to the minimum of 20% ) speed Modules are a good option to raise the pumpjacks output. With two Speed module 3's the output doubles from 1 to 2 crude oil per second and even more when using additional Beacons ( + another 0.5 oil per beacon per second ).
The formula to determine the modified output is:
Output of unmodified oil field * ( Number of modules in pumpjack * bonus from module ) + output of unmodified oil field * ( number of Beacons * ( number of modules * distribution efficiency ) * bonus from module + 1 )
Example | |
---|---|
For 1 pumpjack on a depleted oil field with two lvl 3 speed modules and 6 beacons with each two lvl 3 speed modules: | 0,1 * ( 2 * 0,5 ) + 0,1 * ( 6 * ( 2 * 0,5 ) 0,5 + 1 ) = 0,5 Crude oil per 1 second. |
Assuming that there will be always 2 modules equipped in pumpjack and beacons, formula can be shortened : | 0,1 + 0,1 * ( 6 * 0,5 + 1 ) = 0,5 Crude oil per 1 second. |
History
- 0.15.0: Pumpjacks can be turned on and off using the circuit network. They can also output the current oil mining rate.
- 0.9.0:
- Introduced