In other languages: Deutsch Français 日本語 Nederlands Polska Русский 中文

Pumpjack: Difference between revisions

From Official Factorio Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 14: Line 14:
}}
}}


'''Pumpjacks''' extract [[Crude Oil|crude oil]] from [[Oil field|oil fields]]. Each [[oil field|oil field]] can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 1.0 multiplied by the field's yield (e.g. 5.4 crude oil for 538% yield) per second. Without speed modules one pumpjack cycle takes one second to complete.  
'''Pumpjacks''' extract [[Crude Oil|crude oil]] from [[Oil field|oil fields]]. Each oil field can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 1.0 multiplied by the field's yield (e.g. 5.4 crude oil for 538% yield) per second. Without speed modules one pumpjack cycle takes one second to complete.  


Extracting oil lowers the field's yield by 1% per 75 pumpjack cycles to a minimum of 10%.
Extracting oil lowers the field's yield by 1% per 75 pumpjack cycles to a minimum of 10%.
Line 23: Line 23:


== Tips ==
== Tips ==
If oil fields are depleted ( to the minimum of 10% ) speed [[Module]]s are a good option to raise the pumpjacks output. With two [[Speed module 3]]'s the output doubles from 0.1 to 0.2 crude oil per second and even more when using additional [[Basic beacon]]s ( 0.25 oil per second ).
If oil fields are depleted ( to the minimum of 10% ) speed [[Module]]s are a good option to raise the pumpjacks output. With two [[Speed module 3]]'s the output doubles from 0.1 to 0.2 crude oil per second and even more when using additional [[Basic beacon]]s ( + another 0.05 oil per beacon per second ).  
 
 
The formula to determine the modified output is:
 
Output of unmodified oil field * ( Number of modules in pumpjack * bonus from module ) + output of unmodified oil field * ( number of Beacons * ( number of modules * distribution efficiency ) * bonus from module + 1 )
 
{| class="wikitable"
!colspan="2" | Example
|-
|For 1 pumpjack on a depleted oil field with two lvl 3 speed modules and 6 beacons with each two lvl 3 speed modules:
|0,1 * ( 2 * 0,5 ) + 0,1 * ( 6 * ( 2 * 0,5 ) 0,5 + 1 ) = 0,5 Crude oil per 1 second.
|-
|Assuming that there will be always 2 modules equipped in pumpjack and beacons, formula can be shortened :
|0,1  + 0,1 * ( 6 * 0,5 + 1 ) = 0,5 Crude oil per 1 second.
|}
 
 


== See also ==
== See also ==

Revision as of 16:55, 11 August 2016

Template:Machinery

Pumpjacks extract crude oil from oil fields. Each oil field can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 1.0 multiplied by the field's yield (e.g. 5.4 crude oil for 538% yield) per second. Without speed modules one pumpjack cycle takes one second to complete.

Extracting oil lowers the field's yield by 1% per 75 pumpjack cycles to a minimum of 10%.

Pumpjacks are limited to an maximum output of 10.0 crude oil per cycle, achieved by an oil field with more than 999% yield.

Pumpjacks output tile location is fixed relative to its orientation.

Tips

If oil fields are depleted ( to the minimum of 10% ) speed Modules are a good option to raise the pumpjacks output. With two Speed module 3's the output doubles from 0.1 to 0.2 crude oil per second and even more when using additional Basic beacons ( + another 0.05 oil per beacon per second ).


The formula to determine the modified output is:

Output of unmodified oil field * ( Number of modules in pumpjack * bonus from module ) + output of unmodified oil field * ( number of Beacons * ( number of modules * distribution efficiency ) * bonus from module + 1 )

Example
For 1 pumpjack on a depleted oil field with two lvl 3 speed modules and 6 beacons with each two lvl 3 speed modules: 0,1 * ( 2 * 0,5 ) + 0,1 * ( 6 * ( 2 * 0,5 ) 0,5 + 1 ) = 0,5 Crude oil per 1 second.
Assuming that there will be always 2 modules equipped in pumpjack and beacons, formula can be shortened : 0,1 + 0,1 * ( 6 * 0,5 + 1 ) = 0,5 Crude oil per 1 second.


See also

Template:MachineNav